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The TM Field

The result of deriving the TM electromagnetic field components Eqs.(6.43)-(6.44) from the $ TM$ potential Eq.(6.83), arising from the corresponding $ TM$ source - all relative to the o.n. cylindrical coordinate basis - have been consolidated into Table 6.5.


Table 6.5: The $ TM$ system: All components of any $ TM$ e.m. field $ (\vec
E,\vec B)$ , as well as those of any four-vector $ TM$ potential $ (\vec A,
\phi)$ , are derived from a single master scalar function $ \Phi ^{TM}$ . Its source scalar $ S^{TM}$ determines the vectorial charge flux vector field, which is purely longitudinal.
$ TM$ Potential
$ \hat A_r$ $ \hat A_\theta$      $ \hat A_z$       $ \phi $
$ 0 $ $ 0 $ $ \frac{\partial \Phi^{TM}}{\partial t}$ $ -\frac{\partial \Phi^{TM}}{\partial z}$
$ TM$ Electric Field
$ \hat E_r$ $ \hat E_\theta$ $ \hat E_z$
$ \frac{\partial }{\partial r}
\frac{\partial \Phi^{TM} }{\partial z}$ $ \frac{1}{r}\frac{\partial }{\partial \theta}
\frac{\partial \Phi^{TM}}{\partial z}$ $ \left(
\frac{\partial^2}{\partial z^2}
-\frac{\partial^2}{\partial t^2} \right) \Phi^{TM} $
$ TM$ Magnetic Field
$ \hat B_r$ $ \hat B_\theta$ $ \hat B_z$
$ \frac{1}{r}\frac{\partial }{\partial \theta}\frac{\partial \Phi^{TM}}{\partial t } $ $ -\frac{\partial }{\partial r}\frac{\partial \Phi^{TM}}{\partial t} $ 0
$ TM$ Source
$ \hat J_r$ $ \hat J_\theta$ $ \hat J_z$ $ \rho$
0 0 $ \frac{\partial r^2 S^{TM}}{\partial t}$ $ -\frac{\partial r^2 S^{TM}}{\partial z}$


The TM master scalar $ \Phi ^{TM}$ for these results satisfies the wave equation

$\displaystyle \boxed{ \left( \frac{1}{r}\frac{\partial}{\partial r}r\frac{\part...
...artial z^2} - \frac{\partial^2}{\partial t^2} \right)\Phi^{TM}=-4\pi S^{TM} }~.$ (687)


next up previous contents index
Next: The TEM Field Up: Cylindrical Coordinates Previous: The TE Field   Contents   Index
Ulrich Gerlach 2007-04-05