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Math 132 Quiz 6 March 4, 2010

1) [5 points] Given f(x,y) = xy2 + ye2x, evaluate f(0, 2).
Soltuion.

2 ( f(0,2) = 0 ⋅ 2 + 2e 2 ⋅ 0) = 0 + 2 = 2

2) [5 points] Given f(x,y) = xyey + ln(2x + 3y), find f xy.
Soltuion.

f = yey + ---1----⋅ 2 x 2x + 3y fxy = ey + yey - -----1-----⋅ 3 ⋅ 2 (2x + 3y)2 6 = ey + yey - ---------2- (2x + 3y)